Nettet7. apr. 2013 · a=5, b= (++a)+ (a++) ++a是先加后计算 a++是先计算后加 即:先算++a … Nettet3. mar. 2024 · (a++-++b); The parser knows, that there is no such thing as an +- or -+ operator on int. So it can split the expression in (a++ - ++b); For (a+++++b); This can be (a+ ++... or (a++ +... but let's first have a look at a simpler expression: int a = 100; int b = 0; -> int c=a+++b; Added variable c of type int with initial value 100
void main() int a=10 b b = a++ + ++a printf( - Examveda
Netteta.预处理命令行必须位于源文件的开头 b.在源文件的一行上可以有多条预处理命令 c.宏名必须用大写字母表示 Nettet⇒ 2 - 3 * 8 [∵ b++ uses current value of b in expression and then increments it, --c decrements c to 8 and then uses this 8 in the expression] ⇒ 2 - 24 ⇒ -22 chicken devonshire recipe
#include main() { int a=1; int b=0; b=++a + ++a; …
Nettet24. mai 2024 · int a = 15, b; b = (a++) + (a++); a = (b++) + (b++); printf("a=%d b=%d", a, b); return (0); } Options: 1. a=63 b=33 2. a=33 b=63 3. a=66 b=33 4. a=33 b=33 The answer is option (1). Explanation: Here, a = 15 and b = (a++)+ (a++) i.e. b = 15+16 = 31 and a =3 2. Now a = (b++) + (b++) = 31 + 32 = 63 and b = 33. Nettet单项选择题 #define能作简单的替代,用宏来替代计算多项式5*x*x+5*x+5的值的函数f,正确的宏定义语句为( )。 A.#definef(x)5*x*x+5*x+5 B.#definef5*x*x+5*x+5 C.#definef(a)(5*a*a+5*a+5) D.#define(5*x*x+5*x+5)f(x) 点击查看答案 Nettetint a = 99; int b = a++; After the execution of these two statements, a will have the … chicken dewormer medication