Weball users that have more than one payment per day with the same account number SELECT user_id, COUNT(*) count FROM PAYMENT GROUP BY account, user_id, date HAVING COUNT(*) > 1 Update If you want to only include those that have a distinct ZIP … WebAug 31, 2014 · 1. I think the accepted answer here would actually delete all the duplicates, rather than preserving one unique value. In case anyone is like me and looking to de-duplicate (rather than delete all duplicates), here's a slightly modified solution: DELETE u FROM `users_acl` u JOIN ( SELECT COUNT (*), MIN (userID) as min_id, MAX (acl) as …
SQL COUNT() with HAVING - w3resource
WebDec 5, 2024 · It finds item rows where quantity >= 60. Groups those together by quantity and order to find items within orders that have the same quantity (>= 60). And then counts those rows and, after counting, filters for those rows where the count > 1 (which is a potential duplicate). To actually "see" this, remove the having clause and add the count to ... WebIf SQL2008 is SQL Server 2008, then you can do this: ;WITH CTE AS ( SELECT *, RN = ROW_NUMBER () OVER ( PARTITION BY url ORDER BY updated DESC) FROM [table] ) DELETE FROM CTE WHERE RN > 1 Share Improve this answer Follow answered Feb 28, 2014 at 19:32 Lamak 68.9k 12 108 115 1 What is this sorcery! far eastern navy shipbucket
MongoDB Greater Than Operator - Dot Net Tutorials
WebIf it's just one row then show that name, otherwise show the number of entries instead. So, just use a CASE expression to check whether count is 1 or greater than 1. You probably need CAST or CONVERT to turn the count number into a string, so the CASE expression always returns the same type (this is how CASE works). WebReturns the smallest integer value that is greater than or equal to a number. COMPARE_DECFLOAT scalar function: Returns a SMALLINT value that indicates whether the two arguments are equal or unordered, or whether one argument is greater than the other. COS scalar function: Returns the cosine of a number. COSH scalar function WebThe following SQL statement lists the employees that have registered more than 10 orders: Example Get your own SQL Server SELECT Employees.LastName, COUNT(Orders.OrderID) AS NumberOfOrders FROM (Orders INNER JOIN Employees ON Orders.EmployeeID = Employees.EmployeeID) GROUP BY LastName HAVING … far eastern new century corp